Reaction of CuSO4·5H2O & SrCl2·6H2O with Water

  • Thread starter Thread starter ray4758026
  • Start date Start date
  • Tags Tags
    Chemical
AI Thread Summary
The discussion focuses on the reactions of copper(II) sulfate pentahydrate (CuSO4·5H2O) and strontium chloride hexahydrate (SrCl2·6H2O) with distilled water. Participants express uncertainty about whether these reactions should be classified as double replacement reactions and seek clarification on the amount of distilled water needed. Questions arise about the potential formation of new hydrates with additional water. The conversation emphasizes the importance of understanding chemical reactions and encourages participants to engage with the forum guidelines for better assistance. Overall, the thread highlights a need for foundational knowledge in chemical reactions involving hydrates.
ray4758026
Messages
4
Reaction score
0
ok what is the reaction of copper(2) sulfate penta hydrate and distilled water

as well strontium chloride hexahydrate and distilled water.:cool:
 
Physics news on Phys.org
We can not help unless you first show some effort. Please read the forum guidelines.
 
o well
CuSO4*5H2O+H2O - ?
Srcl2*6H2O+ H2O - ?
i have no idea if this would be treated as a double replacement or how to do these types of reactions.
 
How much distilled water? Do you expect to form another hydrate containing more water?
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top