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Almost there. You need to solve for N not ω, that is have N by itself on the left side of the equation.
The problem involves a particle attached to a string moving in a circular path on a horizontal table, with the goal of finding the reaction force on the particle in terms of its angular velocity, ω. The setup includes considerations of forces acting on the particle, including gravitational and tension forces, as well as the geometry of the situation.
Participants are actively engaging with the problem, questioning the meaning of "reaction" in this context and exploring the implications of their equations. Some have provided diagrams to clarify their understanding, while others are attempting to derive expressions for the forces involved. There is a recognition of the need to distinguish between different forces and their components.
There is some uncertainty regarding the definitions and roles of the forces involved, particularly the normal force and how it relates to the tension in the string. Participants are also considering the implications of the particle's motion and the conditions for it to remain on the table.
Hm, it indeed gets to N = m (g - 0.4 ω2). And that is the reaction on the particle in terms of ω?kuruman said:Almost there. You need to solve for N not ω, that is have N by itself on the left side of the equation.