REAL QUICK question about how to solve for the period of a simple pendulum?

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SUMMARY

The period of a simple pendulum can be calculated using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. In the discussion, the user incorrectly calculated the period using L = 53.4 meters and g = 9.8 m/s², resulting in T = 14.6 seconds. The correct interpretation of units and the values used is crucial for accurate calculations. Additionally, the user was advised to consider the number of oscillations made in a given time frame for further analysis.

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riseofphoenix
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REAL QUICK question about how to solve for the period of a simple pendulum?

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For part a, I tried using the formula: T = 2π√(L/g)

I did,

T = 2π√(53.4/9.8)
T = 2π√(5.44)
T = 2π(2.33)
T = 14.6 s

But that's wrong... Help please?
 
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What are the units of the length and for g?
 


riseofphoenix said:
For part a, I tried using the formula: T = 2π√(L/g)

I detect a hint you should do it differently:
makes 80.6 complete oscillations in 2.00 min[/size]
:smile:
 

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