Real world Aircraft landing deceleration problem

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SUMMARY

The discussion focuses on calculating the average deceleration of an aircraft that lands at a speed of 104 knots (175.53 ft/sec) and comes to a stop over a distance of 3200 feet. The kinematic formula used is v² = 2aΔx, which allows for the determination of deceleration (a). By rearranging the formula, the average deceleration is calculated as a = v²/(2Δx), providing a clear method for solving the problem.

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  • Understanding of kinematic equations
  • Basic knowledge of physics principles related to motion
  • Familiarity with unit conversions (knots to feet per second)
  • Ability to manipulate algebraic equations
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heloman30
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I'm trying to figure out the average deceleration of an aircraft that touches the ground at 104 knots (175.53 ft/sec) and decelerates to zero in 3200 feet? Does anyone know how to do this? Thank you very much to all who reply.
 
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Use the kinematic formula:
v^2 = 2 a \Delta x

Which gives you:
a = v^2/(2 \Delta x)
 

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