Real world testing bench - trying to check my calculations

Click For Summary
The discussion centers on a homemade 'repeating pendulum hammer' designed for product testing, with specific dimensions and weight provided. The creator estimates the instantaneous force exerted by the hammer upon impact to be between 360 to 420 pounds. A participant highlights the importance of calculating the deceleration of the hammer and suggests considering the target's elasticity for more accurate results. The inquiry seeks validation of the force range and clarification on the test's purpose. Overall, the conversation emphasizes the complexities involved in accurately measuring impact forces in such experimental setups.
leahcim
Messages
1
Reaction score
0
I know this seems like a homework question but the last time I was in a physics class was <ahem> 1982.

For product testing reasons, I have fabricated a (rough, very rough--no laughing at the fabrication/welding) 'repeating pendulum hammer'. Please see "test rig diagram.jpg"

Distance from A to B is 13.5"
Weight of (C) Hammer (pendulum) is 10 pounds

C is raised 90 degrees and then dropped to strike B (30/minute - fyi)

I am assuming away all frictions, incorrect/incomplete angles and time issues.

I believe/calculated the instantaneous force (in pounds/force) at B, exerted by the hammer (C) to be in the range of 360 to 420.

This Rube Goldberg was conceived on a bar napkin talking with a ME. Do the forces fall in that range?

TIA,
leahcim
 

Attachments

  • test rig diagram.jpg
    test rig diagram.jpg
    56.1 KB · Views: 539
Last edited:
Physics news on Phys.org
How did you get this force range?

The important thing here is the deceleration of the 'hammer'. This is in general tough to calculate...you might get close if you can find the elasticity of the target (assuming the 'hammer' is a hard metal).
 
What exactly are you trying to achieve with your test? I do this stuff for a living, so I am always interested.
 
Thread 'What is the pressure of trapped air inside this tube?'

Thread 'What is the pressure of trapped air inside this tube?'

As you can see from the picture, i have an uneven U-shaped tube, sealed at the short end. I fill the tube with water and i seal it. So the short side is filled with water and the long side ends up containg water and trapped air. Now the tube is sealed on both sides and i turn it in such a way that the traped air moves at the short side. Are my claims about pressure in senarios A & B correct? What is the pressure for all points in senario C? (My question is basically coming from watching...
View full post »

Similar threads

Electrical Please double-check my thermal dissipation assumptions
  • · Replies 5 ·
Replies
5
Views
2K