Realisability of the third law?

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SUMMARY

The discussion centers on the entropy equation for a monatomic ideal gas, specifically S=A{3nR[ln(T)]/2+nR[ln(V)]}. The participants analyze the implications of the third law of thermodynamics, which states that entropy (S) approaches zero as temperature (T) approaches absolute zero. They conclude that as T approaches zero, S approaches negative infinity if volume (V) is held constant, raising questions about the interpretation of entropy at absolute zero. The final assertion is that by adjusting the equation to S=BnR[ln(T^(3/2)V+1)], the third law can be satisfied, indicating that S can indeed equal zero at T=0.

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My lecture notes had S=A{3nR[ln(T)]/2+nR[ln(V)]}. A arbitary, is the entropy equation for a monotomic ideal gas.

The third law demands S->0 as T->0. But as T->0 in the above equation, S -> -infinity assuming V fixed.

What is wrong?

Or is it the case that S-> -infinity is equivalent to minimum entropy?

V can be made arbitarily small but non zero so when T=0, the entropy must be smaller than any S when T is non zero. This can only happen if S-> -infinity as if it's a finite number than V can always be made smaller so that there exists a V and T such that S is smaller than S when zero T.
 
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I just realized that S can be combined to get S=AnR[ln(T^(3/2)V)] with A an arbitary constant than do S=BnR[ln(T^(3/2)V+1)] with B to scale S in order to account for the addition of 1 in the logarithm. So T=0 => S=0 and so the third law is satisfied. Is this accurate?
 

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