Rearrangement of spring equations not making sense

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SUMMARY

The discussion centers on the relationship between angular frequency (ω) and frequency (f) in spring mechanics. The correct equations are established as ω = 2πf and f = √(ω/2π). A common misconception is addressed, clarifying that f does not equal ω/2π, but rather involves a square root due to its derivation from the simple harmonic motion equation ω = √(K/M). This distinction is crucial for accurate understanding of spring dynamics.

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KKiefhaber
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Hello All,
Something that has bugged me as I have been working through my Physics notes is the statement:

angular frequency for a spring: ω=2πf AND f=√(ω/2π)

It seems to me that simply rearranging the angular frequency equation would give f=ω/2π.
I am confused as to where the square root is coming from.

Thanks for any clarification anyone can provide.
 
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There must be something wrong with your notes! ω does equal 2∏f and therefore f = 2∏/ω
 
Maybe you got it confused with the simple harmonic motion eq: \omega = \sqrt{K/M} ?
 

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