Recalling the Equation for Slit Width in a Double Slit Interference Experiment

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The discussion centers on finding the equation for the slit width in a double slit interference experiment, specifically in relation to the angle theta of the interference maxima. A participant suggests that the equation for fringe width, W = (Dλ)/S, may be relevant, where W is fringe width, D is the distance from the slits to the screen, λ is the wavelength of light, and S is the slit separation. However, the original poster clarifies that they are seeking the actual size of the slits rather than fringe width. The conversation highlights the need for a formula that directly relates to slit width without relying on intensity measurements. The request for assistance remains open as the specific equation for slit width is not provided.
KBriggs
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Hey all,

I need to get the equation for the slit width in a double slit interference experiment (not the distance between slits) that depends on the angle theta to the intferference maxima, and any distances involved in the typical setup. I found one on the forum that involves the intensity of the maxima, but I have no way to measure intensity. Any help?
 
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KBriggs said:
Hey all,

I need to get the equation for the slit width in a double slit interference experiment (not the distance between slits) that depends on the angle theta to the intferference maxima, and any distances involved in the typical setup. I found one on the forum that involves the intensity of the maxima, but I have no way to measure intensity. Any help?

well do you mean fringe width over here..!if yes then equation goes like this..

W = (Dλ)/S

Where,
W= fringe width
D=distance from slits to screen
λ= WAVELENGTH of light
S=slit seperation(distance between the slits)..

I hope this is the formula you were looking for.
 
Not the fringe width, but the size of the two slits. ie, the size of the larger gaps in the little diagram here.
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