Redo Physics Exam Qs: Find Acceleration & Direction

  • Thread starter Thread starter charitysmama
  • Start date Start date
  • Tags Tags
    Forces Test
AI Thread Summary
The discussion revolves around a physics exam question regarding the acceleration of a book sliding down an incline with friction. The user seeks clarification on calculating the normal force (Fn) and acceleration using the equations for net force and friction. Key points include the correct formulation of the net force as the difference between gravitational force along the incline and the frictional force, leading to a net force of 3.92 N. The conversation emphasizes simplifying the equations by using symbols instead of numbers, which aids in understanding. Overall, the user is guided towards finding the acceleration from the net force calculation.
charitysmama
Messages
10
Reaction score
0
Our professor is letting us redo the questions we missed on our exam for half-credit because the averages for his classes were 50, 60, and 70. I have a couple of q's I am needing help with, please.

What is the acceleration of a 1.8 kg physics book sliding down a 36 degree incline if the coefficient of kinetic friction, uk = 0.452?

What I have so far is Fnetx = Fg sin x (theta) - Ffk. But since Ffk is = uk x Fn, how do I find Fn? Would it be equal to Fg x cos (theta)?

Am I headed in the right direction at all?
 
Physics news on Phys.org
charitysmama said:
What I have so far is Fnetx = Fg sin x (theta) - Ffk. But since Ffk is = uk x Fn, how do I find Fn? Would it be equal to Fg x cos (theta)?

Am I headed in the right direction at all?

Right. You are almost there.
 
Okay... so I got Fnetx = 3.92 N. would Fnety = 0? How would I find acceleration from that? Completely lost after this. Thanks much.
 
I don't know how you could be, after writing down the correct eqn...

If total F is along the plane downward, then
F = component of gravity along plane - frictional force
= mgsin(theta) - uk*mgcos(theta).
 
That is how i got the 3.92 N. So that is all?
 
charitysmama said:
That is how i got the 3.92 N. So that is all?

Why, would you have liked it to be very difficult?

The mass will cancel out, so write the eqn in symbols like I have done. That'll make it even easier and neater.

Cheers.
 
I just knew there had to be something else to finding the acceleration is all. Thanks much for the help.
 
Back
Top