Reducing a Matrix of Variables

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Homework Help Overview

The discussion revolves around a linear algebra problem involving a 4x4 matrix constructed from vectors representing powers of variables. The original poster seeks to prove that this matrix can be row reduced to the identity matrix and to determine the linear independence and span of the vectors in IR^4.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the process of row reducing the matrix and share their attempts at manipulating the rows to achieve the desired form. There are questions about how to eliminate variables and achieve leading ones in the matrix.

Discussion Status

Some participants have provided guidance on specific row reduction steps, while others express challenges in progressing further. Multiple strategies for approaching the row reduction are being explored, but there is no explicit consensus on the next steps.

Contextual Notes

Participants note the complexity of the row reduction process and the difficulty in conveying their methods without visual aids. The discussion highlights the challenges of working with symbolic variables rather than numerical values.

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Homework Statement



Given the following vectors: (don't give values to variables)

V0 = (1 1 1 1) V1 = (x1 x2 x3 x4) V2 = (x1^2 x2^2 x3^2 x4^2)

V3 = (x1^3 x2^3 x3^3 x4^3)

a) prove that the 4x4 matrix A, whose columns are the vectors above, row reduces to the 4x4 identity matrix.

b) Do the Vectors above span IR^4? Are these vectors linearly independent?


Homework Equations



No equations, just have to know how to row reduce, etc...

If I'm not mistaken, an identity matrix is one in which the leading entries are all 1's and descend diagonally.

The Attempt at a Solution



It's hard to show via keyboard what I did, but I first created the matrix (so the first column is all ones, etc...). Then I row reduced to get rid of the last 3 ones of the first coloumn by the following operation:

(-1)R1 + R2 -- (-1) R1 + R3 -- (-1)R1 + R4

So now my first column has a leading one (in terms of rows) followed by all zeros below it. However, I'm left with a mix of variables in the other columns (like -x1 + x2, etc...) that I can't figure out how to get rid of! I keep going in circles.

Can anyone help me? I realize it's hard to describe this in words and can't attach a windows journal file for reference...

Thank you!
 
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(Click on the formulas to see the LaTeX code used.)
So your matrix is
\begin{bmatrix}1 & x_1 & x_1^2 & x_1^3 \\ 1 & x_2 & x_2^2 & x_2^3 \\ 1 & x_3 & x_3^2 & x_3^3 \\ 1 & x_4 & x_4^2 & x_4^3\end{bmatrix}

Your first row reductions gives
\begin{bmatrix}1 & x_1 & x_1^2 & x_1^3 \\ 0 & x_2- x_1 & x_2^2- x_1^2 & x_2^3- x_1^3\\ 0 & x_3- x_1 & x_3^2-x_2^3 & x_3^3- x_1^3 \\ 0 & x_4- x_1 & x_4^2- x_1^2 & x_4^3- x_1^3\end{bmatrix}

Now the obvious next step is to divide the second row by x_2- x_1- and that is not as complicated as you might think. Remember that x_2^2- x_1^2= (x_2- x_1)(x_2+x_1) and that x_2^3- x_1^3= (x_2- x_1)(x_2^2+ x_2x_1+ x_1^3.
 
Last edited by a moderator:
Great! thank you, I did that, now I have a leading one in the second row. I;ve tried the next step two ways,

1) eliminate second entry of first row
2) make all entries below leading one of second row 1's

But neither helps me move forward
 
I also tried first obtaining the diagonal 1's that I need, but it gets too messy!
 

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