Reduction formula question (int by parts)

thomas49th
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Homework Statement


Let I_{n} = \int^{2}_{0} x^{n}e^{x} dx where n is a positive integer. Use integration by parts to show
that

<br /> 2^{n}e^{2} - nI_{n-1}<br />

By first finding

I_{1} = \int ^{2}_{0} xe^{x} dx
find I2 and I3.

Homework Equations



I'm sure your all aware of the formula for Int by parts. We'll take the e^{x} function as the one to integrate and the x^{n} as the one to differentiate.

The Attempt at a Solution

So use integration by parts to find In:

x^{n}e^{x} - n\int^{2}_{0}x^{n-1}

Well that's
x^{n}e^{x} - nI_{n-1}
is it not?

So now put the limits in

[x^{n}e^{x} - nI_{n-1}]^{2}_{0}

[2^{n}e^{2} - nI_{n-1}] - [ - nI_{n-1}]
but that's isn't right because I'm getting no nI_{n-1} because they cancel!

Where have I gone wrong?

Thanks
Thomas
 
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thomas49th said:
So use integration by parts to find In:

x^{n}e^{x} - n\int^{2}_{0}x^{n-1}

Well that's
x^{n}e^{x} - nI_{n-1}
is it not?

The step is correct but neither of them represent I_n. The Integration by parts formula for definite integrals is \int^b_a u(x) \frac{dv(x)}{dx} dx = u(b)v(b)-u(a)v(a) - \int^b_a v(x) \frac{du(x)}{dx}.

You have put in the limits of integration for the second term, but not the first.
 
thomas49th said:

Homework Statement


Let I_{n} = \int^{2}_{0} x^{n}e^{x} dx where n is a positive integer. Use integration by parts to show
that

<br /> 2^{n}e^{2} - nI_{n-1}<br />
You omitted part of the statement above. Show that 2ne2 - nIn - 1 equals what or does what?
thomas49th said:
By first finding

I_{1} = \int ^{2}_{0} xe^{x} dx
find I2 and I3.


Homework Equations



I'm sure your all aware of the formula for Int by parts. We'll take the e^{x} function as the one to integrate and the x^{n} as the one to differentiate.

The Attempt at a Solution




So use integration by parts to find In:

x^{n}e^{x} - n\int^{2}_{0}x^{n-1}

Well that's
x^{n}e^{x} - nI_{n-1}
is it not?

So now put the limits in

[x^{n}e^{x} - nI_{n-1}]^{2}_{0}

[2^{n}e^{2} - nI_{n-1}] - [ - nI_{n-1}]
but that's isn't right because I'm getting no nI_{n-1} because they cancel!

Where have I gone wrong?

Thanks
Thomas
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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