Reduction of differntial equation

  • Thread starter Thread starter delsoo
  • Start date Start date
  • Tags Tags
    Reduction
delsoo
Messages
97
Reaction score
0

Homework Statement



for this question, i 'm only able reduce it to become x dv/dx = (v^2 + 1) / v ... i have checked it several times, i just couldn't find my mistake...

Homework Equations





The Attempt at a Solution

 

Attachments

  • DSC_0143~3[1].jpg
    DSC_0143~3[1].jpg
    19 KB · Views: 416
  • DSC_0144~2[1].jpg
    DSC_0144~2[1].jpg
    41.4 KB · Views: 390
Physics news on Phys.org
delsoo said:

Homework Statement



for this question, i 'm only able reduce it to become x dv/dx = (v^2 + 1) / v ... i have checked it several times, i just couldn't find my mistake...

Homework Equations



The Attempt at a Solution

What is \displaystyle \ \int\frac{v}{v^2+1}\,dv\ ?
 
ln (V+1 ) as in my working
 
delsoo said:
ln (V+1 ) as in my working

$$\frac v {v^2+1} \ne \frac v {v(v+1)}$$
 
why can't i do in this way?
 
Because you can't make up your own algebra rules.$$
\frac v {v(v+1)}= \frac v {v^2+v} \ne \frac v {v^2+1}$$
 
SammyS said:
What is \displaystyle \ \int\frac{v}{v^2+1}\,dv\ ?

delsoo said:
ln (V+1 ) as in my working
Take the derivative of ln (V+1 ) .

It's 1/(V+1) .


To do that integration, the substitution, u =(v2+1) works very nicely .
 
Back
Top