Refractive index question - light beam around the world

jadejones
Messages
2
Reaction score
0
1. The refractive index of the Earth’s atmosphere is
n = 1.01 + α(R − r),
where α is a constant, r is the radial distance from the Earth’s centre and
R = 6.4 × 10^6 m is the Earth’s radius. By considering a path comprising a series of
total internal reflections or otherwise, find a value of α for which a light ray emitted
horizontally close to the Earth’s surface would go around the Earth. (The effects of
absorption may be ignored and the Earth may be taken to be a perfect sphere of radius
R.)



2. Homework Equations
n1sin(x1)=n2sin(x2)

3. The Attempt at a Solution
I really have no idea what to do as I understand the refractive index is constantly changing?
Don't know where to start, any help would be much appreciated.
 
Physics news on Phys.org
Think of a wavefront launched horizontally. Realize that the top of this wavefront will move faster than the bottom, since n is lower at higher altitudes ... yet the wavefront phasing across its front has to be the same for all heights - whar does that requirement impose on grad(n)?
 
rude man said:
Think of a wavefront launched horizontally. Realize that the top of this wavefront will move faster than the bottom, since n is lower at higher altitudes ... yet the wavefront phasing across its front has to be the same for all heights - whar does that requirement impose on grad(n)?

Thank you very much for your reply, are you suggesting the light curves around the world? I considered this but thought that only really happened at black holes, or have I misunderstood your response?
 
jadejones said:
Thank you very much for your reply, are you suggesting the light curves around the world? I considered this but thought that only really happened at black holes, or have I misunderstood your response?

I never heard of the herm 'light curves around the world' per se but that is what I had in mind. And I know next to zilch about black holes.

Can you go from there?

BTW the problem did not state that it was possible, it just asked what the n gradient had to be were it possible.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.

Similar threads

Back
Top