Regarding resistivity in heating coils

AI Thread Summary
In heating coils, the relationship between resistance and heat generation is clarified by the formula for power, which is E^2/R. This indicates that for a fixed voltage (E), decreasing resistance (lower ohms) results in a higher heating rate. Higher resistance leads to less current flowing through the circuit, which reduces the overall heat produced despite more energy being dissipated per unit of current. Therefore, a heating element with lower resistance will generate more heat when the circuit is closed. Understanding this principle is crucial for designing effective vaporization devices.
s3nka
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I have a question regarding "ohm level" in a heating element in the design of a device designed to vaporize a liquid.

I thought I had a pretty solid understanding of this but I've been told that I was wrong.

So, I thought that if you increase the resistance (higher ohm) in a heating element within a circuit you would also increase the amount of energy lost as heat which would also mean that the heating element would get hotter compared to a device with lower resistance (lower ohm).

Another designer told me that it's the other way around. The lower the "ohms" the hotter the heating element will become one the circuit is closed.

This makes absolutely no sense to me because in my understanding the larger the resistance the more energy is dissipated as heat and therefore the hotter the heating element becomes.

Could someone explain to me where I am making an error in my understanding?

Thank you ladies and gentlemen
 
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Hi s3nka. Welcome to physics forums.

The heating rate is E2/R, so, for fixed E, the heating rate increases with decreasing resistance.

Chet
 
Thanks for the quick response but I still don't quite understand why that if you have more resistance there isn't more electrical energy lost as heat and as a result more heat dissipated by the heating element (resistor)
 
Because if the resistance is too high, not very much current is flowing.
 
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