Relation between binding free energy and solubility

[Chirag740]

Suppose we have a ligand binding to a receptor in solvent medium. I am interested to know whether there is any relation between "Binding free energy" and "Solubility".

Extemely sorry if I posted my question in the wrong section. I'd be glad if anyone could help me out with this.

Regards,
Chirag V. Vora
Department of Pharmacoinformatics,
Block - A, Bioinformatics Infrastructure Facility,
National Institute of Pharmaceutical Education and Research (NIPER)
Sector 67, S.A.S. Nagar,
Punjab (INDIA) - 160 062

 

[DrDu]

That's not only a question of energetics but even more of entropy.
The equilibrium constant for dissociation can be calculated from
\Delta G=\Delta H -T \Delta S \approx \Delta U -T \Delta S
where \Delta U is the dissociation energy per mole and in solution is practically equal to the enthalpy change,
and \Delta S the entropic change due to dissociation.
The equilibrium constant K is
K=\exp(\Delta G/RT)

Edit: Excuse me, I overread "free" in your post.
\Delta G is the free energy of binding, so the relation is quite direct.