Relation between Gamma and Poisson

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The discussion focuses on proving the relationship between a gamma distribution and a Poisson distribution, specifically showing that Pr(X>t) equals Pr(Y≤r−1) for X following a gamma distribution and Y following a Poisson distribution. The proof involves induction on the parameter r, starting with the base case of r=1, which corresponds to an exponential distribution. Participants highlight the need to express the probability density functions for both distributions and demonstrate their equality in the base case. The challenge lies in simplifying the equations to show that the probabilities are equivalent. Understanding the induction process is crucial for completing the proof.
lily_w
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I'm having trouble doing a classic proof (integration par part and induction on r) for this :

Pr(X>t)=Pr(Y ≤r−1), where X follows a gamma Γ(α = r, β = 1/λ) and Y a Poisson P (λt).
Start with r = 1 (exponential distribution).

I don't really understand what induction on r really means.

I tried just showing the basic density equation for both (Gamma and Poisson) but i don't know how to make them simplify into the same thing.
 
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First, you want to show that the statement Pr(X>t) = Pr(Y≤r-1) is true when r=1. This is the base case. Next, you assume the statement holds when r=k and show that the statement is true for r=k+1. That's what you need to do for a proof by induction.

When r=1, what are the probability density functions for X and Y? Write down expressions for Pr(X>t) and Pr(Y≤0) and show they are equal.
 
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