Poisson and Gamma Distributions

[Artusartos]

Let Y|X be a Poisson(X), and X be Gamma(\alpha, \beta). Find E(X|Y)...

Since Y|X is Poisson(X), we have f(Y|X)= \frac{m^x e^{-m}}{x!}...

Since X is Gamma(\alpha, \beta), we have f(x)= \frac{x^{\alpha-1} e^{-x/B}}{\Gamma(\alpha) \beta^{\alpha}}...

Since f(Y|X) = \frac{f(x,y)}{f(x)} ====> f(x,y) = \frac{f(Y|X)}{f(x)}...

So now we have...

f(x,y) = \frac{(\frac{m^x e^{-m}}{x!})}{\frac{x^{\alpha-1} e^{-x/B}}{\Gamma(\alpha) \beta^{\alpha}}}

So now I have to find f(y), but I'm sort of confused...because the poisson distribution is discrete while the gamma distribution is continuous...so do I need to handle them separately?

Thanks in advance.

 

[Ray Vickson]

Let Y|X be a Poisson(X), and X be Gamma(\alpha, \beta). Find E(X|Y)...

Since Y|X is Poisson(X), we have f(Y|X)= \frac{m^x e^{-m}}{x!}...

Since X is Gamma(\alpha, \beta), we have f(x)= \frac{x^{\alpha-1} e^{-x/B}}{\Gamma(\alpha) \beta^{\alpha}}...

Since f(Y|X) = \frac{f(x,y)}{f(x)} ====> f(x,y) = \frac{f(Y|X)}{f(x)}...

So now we have...

f(x,y) = \frac{(\frac{m^x e^{-m}}{x!})}{\frac{x^{\alpha-1} e^{-x/B}}{\Gamma(\alpha) \beta^{\alpha}}}

So now I have to find f(y), but I'm sort of confused...because the poisson distribution is discrete while the gamma distribution is continuous...so do I need to handle them separately?

Thanks in advance.

What is P{Y = k} for k = 0,1,2,... ? What is P{x < X < x+dx|Y=k} for k = 0,1,2, ... ?

RGV

 

[Artusartos]

What is P{Y = k} for k = 0,1,2,... ? What is P{x < X < x+dx|Y=k} for k = 0,1,2, ... ?

RGV

When you say P(Y=k), do you mean P(Y=k|X)? (since we are told that it is poisson when it is conditioned by X...) However, if you mean that it is not P(Y=k|X)...actually that was what I was trying to compute by integrating out x from the continuous part...and then looking at the discrete part (but I was confused, because I wasn't sure if I could handle them separately).

P(Y=k) = \sum \frac{m^k e^{-m}}{k!}

and...

P(x &lt; X &lt; x+dx|Y=k) = \frac{P(x &lt; X &lt; x+dx) ∩ P(Y=k)}{P(Y=k)}

 

[Ray Vickson]

When you say P(Y=k), do you mean P(Y=k|X)? (since we are told that it is poisson when it is conditioned by X...) However, if you mean that it is not P(Y=k|X)...actually that was what I was trying to compute by integrating out x from the continuous part...and then looking at the discrete part (but I was confused, because I wasn't sure if I could handle them separately).

P(Y=k) = \sum \frac{m^k e^{-m}}{k!}

and...

P(x &lt; X &lt; x+dx|Y=k) = \frac{P(x &lt; X &lt; x+dx) ∩ P(Y=k)}{P(Y=k)}

Where do you get the formula
P(Y=k) = \sum \frac{m^k e^{-m}}{k!}? What is m? what are you summing over?

The way I read the problem, we have
P\{ Y = k | X = x \} = \frac{x^k e^{-x}}{k!}.
That is *exactly* what the problem says!

Now, of course, you need to find P{Y = k}, an unconditional probability.

RGV

 

[Artusartos]

Where do you get the formula
P(Y=k) = \sum \frac{m^k e^{-m}}{k!}? What is m? what are you summing over?

The way I read the problem, we have
P\{ Y = k | X = x \} = \frac{x^k e^{-x}}{k!}.
That is *exactly* what the problem says!

Now, of course, you need to find P{Y = k}, an unconditional probability.

RGV

The reason that I wrote summation is because this is the cumulative distribution...not the probability mass function. So for continuous cases, the cdf is the integral of the pdf, and for discrete cases the cdf is the summation of the pmf...and what you're summing over depends on the question. Isn't that correct?

 

[Ray Vickson]

The reason that I wrote summation is because this is the cumulative distribution...not the probability mass function. So for continuous cases, the cdf is the integral of the pdf, and for discrete cases the cdf is the summation of the pmf...and what you're summing over depends on the question. Isn't that correct?

OK, fine: you want to find the cdf of something. However, your expression is still lacking in two ways: (i) what is the summation index?; and (ii) what are the summation limits? Just writing Ʃ does not tell anyone whether you are summing over k for fixed m or over m for fixed k, and what the summation limits are.

Anyway, nothing in this question asks about the cdf (unless there are parts of the question you have not written in your first post).

At this point I am finished with this thread.

RGV

 

[Artusartos]

OK, fine: you want to find the cdf of something. However, your expression is still lacking in two ways: (i) what is the summation index?; and (ii) what are the summation limits? Just writing Ʃ does not tell anyone whether you are summing over k for fixed m or over m for fixed k, and what the summation limits are.

Anyway, nothing in this question asks about the cdf (unless there are parts of the question you have not written in your first post).

At this point I am finished with this thread.

RGV

Actually, I wasn't trying to find the cdf at first. But when you asked me to find P{Y = k} and P{x < X < x+dx|Y=k}...P(anything) can be found using the cdf.

Anyways, I'll probably ask my professor about this...