Relationship between hyperbolic cosine and cosine

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SUMMARY

The discussion centers on the relationship between hyperbolic cosine and cosine, specifically addressing the intersection of the hyperbola defined by the equation x² - y² = 1 with the line y = mx. The correct interpretation of hyperbolic cosine is clarified as the x-coordinate of a point on the hyperbola, analogous to how cosine represents the x-coordinate on the unit circle. The confusion arises from the incorrect application of the tangent function instead of the hyperbolic tangent, with the correct relationship being cosh(α) = cos(iα).

PREREQUISITES
  • Understanding of hyperbolic functions, specifically hyperbolic cosine (cosh)
  • Familiarity with trigonometric functions, particularly cosine (cos)
  • Knowledge of the geometric definitions of circles and hyperbolas
  • Basic understanding of Euler's formulas in relation to trigonometric identities
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  • Study the properties of hyperbolic functions, focusing on their geometric interpretations
  • Learn about the relationship between hyperbolic and circular functions using Euler's formulas
  • Explore the concept of arc length in both circular and hyperbolic contexts
  • Investigate the applications of hyperbolic functions in various mathematical fields, such as calculus and complex analysis
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Mathematicians, physics students, and anyone interested in the geometric interpretations of hyperbolic and trigonometric functions.

mnb96
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Hello,

I am considering the hyperbola x^2-y^2=1 and its intersection with the line y=mx. The positive x-coordinate of the intersection is given by: x=\sqrt{\frac{1}{1-\tan^2\alpha}}=\sqrt{\frac{\cos^2 \alpha}{\cos(2\alpha)}}=\cos\alpha \sqrt{\sec(2\alpha)} where we used the identity m=\tan\alpha.

However, using Euler formulas for cosines does not seem to give the relationship: \cosh(\alpha)=\cos(i\alpha).
Am I using a wrong geometrical definition of hyperbolic cosine? I mean, perhaps the hyperbolic cosine is not simply the x-coordinate of the intersection of a ray with the hyperbola?
 
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hello mnb96! :smile:

(i'm not quite following your question, but anyway …)

you need to use m = tanhα :wink:
 
mnb96 said:
Hello,

I am considering the hyperbola x^2-y^2=1 and its intersection with the line y=mx. The positive x-coordinate of the intersection is given by: x=\sqrt{\frac{1}{1-\tan^2\alpha}}=\sqrt{\frac{\cos^2 \alpha}{\cos(2\alpha)}}=\cos\alpha \sqrt{\sec(2\alpha)} where we used the identity m=\tan\alpha.

However, using Euler formulas for cosines does not seem to give the relationship: \cosh(\alpha)=\cos(i\alpha).
Am I using a wrong geometrical definition of hyperbolic cosine? I mean, perhaps the hyperbolic cosine is not simply the x-coordinate of the intersection of a ray with the hyperbola?
Yes, you are. The line y= mx has nothing to do with it. 'cos(t)' is defined as the x-coordinate of the point (x,y) at distance t around the circumference of the circle, x^2+ y^2= 1 from (1, 0).

So 'cosh(t)' is the x-coordinate of (x, y) at distance t around the curve x^2- y^2= 1 from (1, 0).
 
thanks for your replies!

@Hallsofivy: when you said "distance around the circumference" you meant distance in terms of arc length of the circumference of the unit circle?
 
mnb96 said:
@Hallsofivy: when you said "distance around the circumference" you meant distance in terms of arc length of the circumference of the unit circle?

yes he did :smile:

arc-distance round a circle is proportional to angle,

and arc-distance round a hyperbola is proportional to hyperangle :wink:
 

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