Relative population density of stars and galaxies

AI Thread Summary
The discussion focuses on calculating the average population density of stars and galaxies around the Sun. The number of stars within 17 light-years is 75, while there are 26 galaxies within 4 million light-years. To find the density, the number of stars and galaxies must be divided by the volume of spheres defined by their respective distances. The correct approach emphasizes that the calculations involve the volumes of spheres, not the individual volumes of stars or galaxies. Understanding this distinction is crucial for obtaining the correct density values.
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Homework Statement



The number of stars around the Sun, within a distance of 17 ly, is 75. The number of galaxies in the local group, within a distance of 4.0 x106 ly from the Sun, is 26.

Calculate the average popluation density, per ly3, of stars and galaxies.

Homework Equations

The Attempt at a Solution


Stars: 75/173
Galaxies: 26/(4.0 x106)3

But the answers I obtain from my attempt is incorrect :s
Help please!
 
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What is the shape of the volume element?
 
voko said:
What is the shape of the volume element?

The question assumes that the Sun is a sphere. So I suppose the volume element is sphere.
 
What's the volume of the sphere?
 
voko said:
What's the volume of the sphere?
I think my brain went dead, because I got it after saying that we assume the Sun as the volume of a sphere.

So basically ly is the radius and we divide 75 by the volume of the star and galaxy to get the two answers :smile:

Am I right?! Please approve! :approve:
 
Pedantry: it is not the volume of the star, and not the volume of the galaxy. It is the volumes of two balls of the specified radii.

:)
 
voko said:
Pedantry: it is not the volume of the star, and not the volume of the galaxy. It is the volumes of two balls of the specified radii.

:)

Hah, I would say not pedantry at all! It's kind of a crucial detail that you're dividing the number of objects by the volume of the region. I hope the OP gets this now.
 
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