Relative Velocity - is the answer correct?

AI Thread Summary
The discussion revolves around calculating the velocity of an ant relative to the ground while it crawls on a stick being dragged at an angle. The ant's velocity is given as 20mm/s west, and the stick's velocity is 50mm/s at a 25-degree angle north of west. The calculations involve breaking down the stick's velocity into its x and y components and then combining these with the ant's velocity. The final result shows that the ant's velocity relative to the ground is 68.6mm/s at an angle of 18 degrees north of west. The solution is confirmed to be correct by multiple participants in the discussion.
Mezz
Messages
2
Reaction score
0

Homework Statement


An ant with a velocity of 20mm/s [W] crawls on a stick that is being dragged [W25 N] at 50mm/s. what is the velocity of the ant relative to the ground?

Homework Equations


Let A = ant, Let S=stick, Let G=ground, Let N and W be positive. Vag=?, Vas=20mm/s [W], Vsg=50mm/s[W25N]

The Attempt at a Solution


Vag=Vas + Vsg

Vas = Vasx + Vasy
= 20mm/s + 0mm/s

Vsgx = Vsg(cos25)
=50mm/s(cos25)
=45.315 mm/s

Vsgy= Vsg(sin25)
=50mm/s(sin25)
=21.130mm/s

Vagx=Vasx +Vsgx
=20mm/s+45.315mm/s
=65.3mm/s

Vagy= Vasy + Vsgy
= 0mm/s +21.130mm/s
=21.1mm/s

V2ag=V2agx +V2agy
Vag= (65.3mm/s)2+(21.1mm/s)2 - This is square root as well
Vag=68.6mm/s

Tan@= O/A
@= Tan-1(21.1mm/s / 65.3mm/s)
@= 17.9
@=18

Therefore the Ant s velocity relative to the ground is 68.6mm/s [W18N]
 
Physics news on Phys.org
That's what I get as well.
 
BiGyElLoWhAt said:
That's what I get as well.
Thank you!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top