Relativistic Antiproton Protion

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The discussion centers on the derivation of the kinetic energy required for a proton to produce a static antiproton, specifically focusing on the formula "m^2c^4 - p^2c^2 = m_0^2c^4." This equation is a rearrangement of Einstein's energy-momentum relation, which states that the energy squared equals the rest mass squared times the speed of light to the fourth power plus the momentum squared times the speed of light squared. The confusion arises from the interpretation of the terms, with one participant clarifying that the formula applies to any proton, including the moving one. The invariant nature of the equation is emphasized, confirming its validity for the scenario discussed. The conversation concludes with an acknowledgment of the clarification provided.
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This isn't really so much of a homework problem, but I'm reading this webpage, and there's one part of the derivation of the required proton KE needed to produce a static antiproton.

The part that's puzzling me is

"and using... m2inc4 - p2inc2 = m20c4 "

I don't see where this formula is coming from. I can see the resemblance to the invariant, but the RHS deals with the moving proton, and the LHS only has the mass of a single proton, I'm confused as to why it's not (2m0)2c4.

Thanks for any help.
 
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alex3 said:
The part that's puzzling me is

"and using... m2inc4 - p2inc2 = m20c4 "

I don't see where this formula is coming from.
This is just a rearrangement of the usual Einstein formula:

E^2 = m_0^2c^4 + p^2c^2

m^2c^4 = m_0^2c^4 + p^2c^2

m^2c^4 - p^2c^2 = m_0^2c^4

where m is the 'relativistic mass'.

(This formula is derived on the page just before the one you linked.)

I can see the resemblance to the invariant, but the RHS deals with the moving proton, and the LHS only has the mass of a single proton,
I'm not sure what you mean. This is the invariant. It's true for any proton, including the incoming one.
 
Aha of course, elementary really. Thanks very much for the clarification!
 
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