Relativistic motion of the bullet

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Homework Help Overview

The discussion revolves around a problem involving the relativistic motion of a bullet as observed from a distant camera. The bullet has a proper length \( l_0 \) and is moving at a velocity \( v \) at an angle \( \beta \) relative to the line connecting the camera and the bullet. The task is to determine the length of the bullet as seen from the camera, specifically how much of a ruler is obscured by the bullet.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants express confusion regarding the relevance of the angle \( \beta \) in the context of length contraction. Some question whether the bullet's motion is solely along the x-direction in the camera's reference frame. Others discuss the implications of the camera's position relative to the bullet and the ruler.

Discussion Status

There is an ongoing exploration of the problem's setup, with hints provided about length contraction occurring along the direction of motion. Some participants are attempting to clarify their understanding of the problem's assumptions and the role of the camera's perspective.

Contextual Notes

Participants note potential contradictions in the problem statement and express uncertainty about the completeness of the question. The discussion includes references to specific assumptions about the distances involved and the timing of light signals from the bullet to the camera.

Caneholder123
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1. A distant camera is taking an image of a bullet of proper length l_0 and velocity v. The bullet is moving on a straight line which is parallel to the ruler (a bit behind the bullet, when it is watched from the camera). An angle between the velocity vector and the line that connects the camera with the bullet is \beta. Determine the length of the bullet as seen from the camera, i.e. how much of the ruler is hidden.

Homework Equations


Lorentz transformations, from which the formula for the length contraction follows:
l=\frac {l_0}{\gamma}

The Attempt at a Solution


I just don't get this problem. Why is the angle \beta given? Under the assumptions that the camera is far from the bullet and that the bullet is close to the ruler, isn't the length of the bullet measured just the contracted length? Angle \beta will be changed, but I just can't see where it goes in this story.
 
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Hint: length contraction always occurs along the direction of motion.
 
PWiz said:
Hint: length contraction always occurs along the direction of motion.
I didn't position the camera reference frame right. Thank you for the help.
 
Do you know the answer bro??
 
Sagar Singh said:
Do you know the answer bro??
No, m8. I don't get it. Doesn't the bullet move only move in x-direction in camera reference frame too, or I am not reading this properly? Sorry for being late with the reply, I was extremely busy last two days.
 
Caneholder123 said:
No, m8. I don't get it. Doesn't the bullet move only move in x-direction in camera reference frame too, or I am not reading this properly? Sorry for being late with the reply, I was extremely busy last two days.
actually there are many contradictions in this question, i think this is not complete question
 
Considering the approximations that the camera is far away from the bullet and that the bullet is right in front of the ruler, projection is just the length measured from the camera reference frame. And that length is \frac {l_0}{\gamma} because the motion is just in one direction.
 
PWiz said:
Hint: length contraction always occurs along the direction of motion.
I realize that. Can you help me with the setup of the problem?
 
In case you're still wondering how to solve this: This exercise is from the "Problembook in Relativity and Gravitation" (Problem 1.5), see for example here:
http://apps.nrbook.com/relativity/index.html (need flash).

The key point is, that your camera measures the distance by receiving the photon from the front and from the back of the bullet simultaneously.
That means that the photon from the back of the bullet need so be sent earlier than from the front. In this time the bullet travels some length.

The solution is given in the book.
 

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