Relativistic velocity scenario

In summary, if a ship starts accelerating continuously while another remains at rest in the observer's frame, there will be a reference frame where the difference between them is just below 2c. However, in the observer's frame, the difference will never reach the speed of light. In order for the observer to see a difference just below 2c, they would need to follow the first ship that leaves and accelerate until they see the other ship at just below the speed of light, and then stop accelerating and wait for the first ship to reach near the speed of light.
  • #1
calinvass
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Lets suppose there is an observer at a certain distance from a planet that is moving at 0.9c as seen by the observer. We take as a reference, a frame where the observer is at rest. A spaceship leaves the planet and begins accelerating relative to the planet in the oposite direction. The observer should see the spaceship decelerating and at some point having zero velocity, then the ship will apear to acceletate further in the opposite direction. Relative to the observer I suppose it is possible in principle can reach 0.9c. But when the observer checks the relative velocity between the planet and the spaceship it will conclude the spaceship managed to change its velocity bu 1.8c. Is this correct ?
 
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  • #3
calinvass said:
when the observer checks the relative velocity between the planet and the spaceship it will conclude the spaceship managed to change its velocity bu 1.8c.

You have described this incorrectly. A correct description is: when the observer checks the difference in velocity, in his reference frame, between the planet and the spaceship, he will find it to be 1.8c. This is because the ship and the planet are moving in opposite directions, each at 0.9c, in his frame.

However, this 1.8c is not "the relative velocity between the planet and the spaceship". The latter term means either the velocity of the planet in the spaceship's frame, or the velocity of the spaceship in the planet's frame. (Numerically these are the same, they only differ in sign.) This can be found by the relativistic velocity addition formula: ##(0.9 + 0.9) / (1 + 0.9^2)##, which gives about 0.995c.
 
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Thank you for the correction. In other words the observer sees the spaceship and the planet are moving away from each other faster than the speed of light. But that is acceptable since the observer basically sees two objects traveling at 0.9c that happen to be in opposite directions.
But it is still funny because the ship will see the planet going away at 0.995c and the observer can talk to the crew and tell them he sees them separating at 1.9c.

Another scenario can be with two spaceship. They both are initially in a frame at rest then continuously accelerate (constant proper acceleration) in opposite directions. The relative velocity between them can in principle will approach c, but there must exist a reference frame where the spacecraft are separating away from each other at more than 1.9 c after a certain amount of time has passed.
 
  • #5
calinvass said:
there must exist a reference frame where the spacecraft are separating away from each other at more than 1.9 c after a certain amount of time has passed.
Yes. The frame in which they were originally rest in one of these.
 
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  • #6
calinvass said:
In other words the observer sees the spaceship and the planet are moving away from each other faster than the speed of light.

No. He sees the distance between them increasing at a rate that's faster than the speed of light. He knows, as a result of a calculation, how fast they move relative to each other. Do the calculation incorrectly and you get 1.8 c. Do it correctly and you get 0.95 c.
 
  • #7
The important takeaway here is that it is still the case that nothing with mass can reach or exceed the speed of light relative to you, but you can observe two different things with mass approach or move apart from each other at a rate faster than c (but always slower than 2c).

From your perspective, light emitted from the ship will barely outpace the ship at 0.1c, and slowly catch up to Earth at 0.1c, so nothing is actually moving faster than light relative to you.
 
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  • #8
Nugatory said:
Yes. The frame in which they were originally rest in one of these.

Supposing only one ship starts to accelerate continuously , and the other remains still in the observer's frame. Again at some point I suppose there should be a frame where the difference between them is 1.9c (or whatever value greater than c we choose, depending on how much we wait), although in the observer's frame, this time the difference will never reach c.
 
  • #9
calinvass said:
Supposing only one ship starts to accelerate continuously , and the other remains still in the observer's frame. Again at some point I suppose there should be a frame where the difference between them is 1.9c (or whatever value greater than c we choose, depending on how much we wait), although in the observer's frame, this time the difference will never reach c.
If by "whatever value greater than c we choose" you mean "whatever value greater than c and less than 2c we choose", and by "the observer's frame" you mean "the frame in which both ships are initially at rest", then yes.
 
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Thank you. Of course, less than 2c. But in this case, I think, if the observer remains in the frame where both spacecraft were at rest, it will only see a maximum just below c. (In this second example one of the spacecraft remains in the initial position) In order to see a difference of just below 2c it needs to follow the first spacecraft that leaves and to accelerate until it sees the spacecraft that remained at the initial position, just below c, then to stop accelerating and wait until the first one reaches near c.
 
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  • #11
calinvass said:
Thank you. Of course, less than 2c. But in this case, I think, if the observer remains in the frame where both spacecraft were at rest, it will only see a maximum just below c. (In this second example one of the spacecraft remains in the initial position) In order to see a difference of just below 2c it needs to follow the first spacecraft that leaves and to accelerate until it sees the spacecraft that remained at the initial position, just below c, then to stop accelerating and wait until the first one reaches near c.
Not sure exactly what this all means, but the situation is fairly simple:

1) Nothing can move in any inertial reference frame faster than c.
2) Two objects can move apart in a "stationary" reference frame faster than c.
a) Suppose two objects are moving apart faster than c in a "stationary" reference frame. In either of their moving reference frames, the other is not moving faster than c.
b) A person in the "stationary" frame can use SR to understand why a person in one moving reference frame would say that the other moving object was not moving away faster than c.​
 
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  • #12
FactChecker said:
Not sure exactly what this all means, but the situation is fairly simple:

1) Nothing can move in any inertial reference frame faster than c.
2) Two objects can move apart in a "stationary" reference frame faster than c.
a) Suppose two objects are moving apart faster than c in a "stationary" reference frame. In either of their moving reference frames, the other is not moving faster than c.
b) A person in the "stationary" frame can use SR to understand why a person in one moving reference frame would say that the other moving object was not moving away faster than c.​

Thank you, I agree with the above statements. My example uses them but if what I said is correct (to me it looks clear) it may not be so obvious to say how it the thought experiment works.
 

1. What is the concept of "relativistic velocity scenario"?

The relativistic velocity scenario refers to the effects of relativity on the motion and velocity of objects. This includes the concept of time dilation and length contraction, which occur at high speeds and close to the speed of light.

2. How does the theory of relativity affect velocity calculations?

According to the theory of relativity, the speed of light is constant and the same for all observers. This means that as an object approaches the speed of light, its velocity cannot exceed it, even though its acceleration may continue to increase.

3. Can an object exceed the speed of light in a relativistic scenario?

No, according to the theory of relativity, the speed of light is the maximum speed that can be reached by any object. This is because as an object approaches the speed of light, its mass increases infinitely, making it impossible to reach or exceed it.

4. How does the concept of time dilation impact objects moving at high velocities?

Time dilation refers to the slowing down of time for an object moving at high velocities. This means that time appears to pass slower for objects moving at high speeds compared to those at rest. This effect becomes more pronounced as an object approaches the speed of light.

5. Is the theory of relativity applicable to all objects and scenarios?

Yes, the theory of relativity is a fundamental principle of physics and applies to all objects and scenarios, regardless of size or speed. Its effects may not be noticeable in everyday situations, but become significant at high velocities and in extreme gravitational fields.

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