Relativity & Light: Explaining an Observation Phenomenon

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    Light Relativity
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Discussion Overview

The discussion revolves around the phenomenon of light speed as observed from different reference frames, particularly in the context of special relativity. Participants explore the implications of traveling at the speed of light and how light is perceived by observers in relative motion.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant questions whether an observer would see light traveling at twice the speed of light if they were traveling at light speed themselves.
  • Another participant explains that the concept of 'traveling at the speed of light' lacks meaning without considering relative motion between observers, referencing Newton's perspective on motion.
  • A participant describes the relativistic addition of velocities, stating that no observer will see another object moving at the speed of light relative to them, due to the rules of velocity addition in relativity.
  • Further, it is noted that all observers perceive light traveling at the same speed (c), regardless of their own motion.
  • One participant provides a mathematical expression for how the speed of an object thrown by a moving observer is calculated relative to a stationary observer, demonstrating that light will always be observed at speed c.
  • A later reply expresses satisfaction with the explanation provided regarding the observation of light speed.
  • A link to a FAQ on the topic is shared for additional reference.

Areas of Agreement / Disagreement

Participants generally agree on the principles of special relativity regarding the speed of light and the relative motion of observers, but the initial question about light speed perception raises some conceptual challenges that are not fully resolved.

Contextual Notes

The discussion includes assumptions about the nature of motion and the definitions of speed in different reference frames, which may not be universally accepted or understood without further clarification.

Who May Find This Useful

This discussion may be useful for individuals interested in the principles of special relativity, the behavior of light in different reference frames, and those seeking clarification on common misconceptions related to speed and motion in physics.

cody628496
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If you are traveling at the speed of light and you were to shine a light the observer wouldn't observe twice the speed of light? Please explain this phenomena to me
 
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The phrase 'travelling at the speed of light' on it's own doesn't mean much, because ( according to Newton) one cannot distinguish 'rest' from a state of uniform motion. It is only meaningful to talk about the relative velocities of objects.

So it's customary to talk about two observers, who have a relative velocity. So each one sees the other approaching or departing.

Given this situation, neither will see the other have a relative velocity equal to the velocity of light (c). This is because the rule for addition of velocities precludes this.

Another postulate of relativity states that all observers see light traveling at the same speed. If either observer emits light, it will be seen by both to be traveling at c m/s.

This is counter-intuitive but that's what SR tells us.
 
If person A is traveling at speed [itex]v_A[/itex] relative to you and throws object B directly away from you at speed [itex]v_B[/itex] relative to himself, that object will have speed, relative to you,
[tex]\frac{v_A+ v_B}{1+ \frac{v_Av_B}{c^2}}[/tex]

Note that, whatever [itex]v_A[/itex] is, if [itex]v_B= c[/itex], that will give
[tex]\frac{v_A+ c}{1+ \frac{v_A}{c}}[/tex]
multiplying both numerator and denominator by c, we have
[tex]\frac{c(v_A+ c)}{c+ v_A}= c[/tex]

So no matter how fast A is moving relative to you, if he shines a light ahead of himself, it will have speed c relative to both of you.
 
Very nice that's the explanation i was looking for.
 

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