Rényi entropy becomes von Neumann entropy

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 3K views
Lapidus
Messages
344
Reaction score
12
In holographic entanglement entropy notes like here, they let alpha go to one in (2.41) and get (2.42). But (2.41) goes towards infinity, when doing that! Can someone explain how alpha --> 1 will make (2.41) into (2.42)? Thank you!

Renyi Neumann.PNG
 
Physics news on Phys.org
You should keep in mind that ## Tr \rho=1 ##. So ## \displaystyle \lim_{\alpha \to 1} \log(Tr \rho^\alpha)=0##. So ## \displaystyle \lim_{\alpha \to 1}S_\alpha(\rho)=\frac 0 0 ## and is indeterminate. To calculate it, you need to use L'Hopital's rule and differentiate the numerator and denominator w.r.t. ## \alpha ## and then take the limit.
 
  • Like
Likes   Reactions: Demystifier, Lapidus and atyy