Representation of spin matrices

bznm
Messages
181
Reaction score
0
I have just started to study quantum mechanics, so I have some doubts.

1) if I consider the base given by the eigenstates of s_z s_z | \pm >=\pm \frac{\hbar}{2} |\pm> the spin operators are represented by the matrices

s_x= \frac {\hbar}{2} (|+><-|+|-><+|)
s_y= i \frac {\hbar}{2}(|-><+|-|+><-|)
s_z=\frac{\hbar}{2}(|+><+|-|-><-|)

but I don't have clear idea of what they correspond to concretely. Considering the Dirac formalism, can they be represented by Pauli's matrices?

s_x=\frac {\hbar}{2} \sigma_x; s_y= i \frac {\hbar}{2} \sigma_y; s_z=\frac {\hbar}{2} \sigma_z

2) I can write a vector using its components, e.g. v=(a,b)
but which are the components of the eigenstates of s_z?

3) If I have a state such as s_x |\phi>=\frac {\hbar}{2} |\phi>
and I want to write it using the base of the eigenstates of s_z,
can I write |\phi>=a|+>+b|->, with |a|^2+|b|^2=1? (I need this condition to have a normalized vector)
Is it equal to \frac {e^{i\theta}}{\sqrt 2}(|+>+|->)?

Many thanks for your help!
 
Physics news on Phys.org
bznm said:
Considering the Dirac formalism, can they be represented by Pauli's matrices?
Yes.

bznm said:
2) I can write a vector using its components, e.g. v=(a,b)
but which are the components of the eigenstates of s_z?
Yes, if you use the representation of the spin operators in terms of Pauli matrices.

bznm said:
can I write
Yes, what you quoted here was a general spin state. You need to fix a and b so that it is actually an eigenvector of s_x.
bznm said:
Is it equal to
... Which you did here. The exponential is an arbitrary phase factor and can be dropped.
 
Thanks a lot!
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

Similar threads

Replies
2
Views
1K
Replies
1
Views
500
Replies
4
Views
1K
Replies
3
Views
2K
Replies
4
Views
1K
Replies
1
Views
412
Back
Top