Representing dv independent of time?

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SUMMARY

This discussion focuses on representing velocity independent of time, particularly in the context of constant and varying acceleration. Key equations highlighted include the basic equations for constant acceleration, such as v = v_o + at and v^2 = v_o^2 + 2as. The conversation explores alternative formulations, such as v = ds/dt multiplied by (dv/dv) and v = (ds/dt) * (da/da), which yield velocity expressions devoid of explicit time dependence. The discussion emphasizes that while numerous formulations exist, many are impractical for real-world applications.

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There are four basic equations for constant acceleration

v = v_o +at
v^2 = v_o^2 +2as
and so on

The first velocity is time dependent, while the second velocity relationship is time independent.

In varying acceleration, we have

v = ∫ a(t) dt

Is there any other way we can define velocity so that it is independent of time, akin to the constant acceleration above?
 
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There are infinite such ways :-)

But most of them aren't useful from practical point of view.

Still I will state one or two for you.

You can write v=ds/dt

v=(ds/dt)*(dv/dv)

[Multiplying by (dv/dv) makes no change]

V=(ds/dv)*(dv/dt)
V=(ds/dv)*a
Since a=dv/dt

On integration this yields your second equation when a is constant.


Another would be

v=(ds/dt)*(da/da)

V=(ds/da)*j

Where j is the jerk, the rate of change of acceleration.

All these equations will give you formula's independent of t. But they will contain other variables which depend on time.


Also
Remember, in steady fluids we define the velocity as a function of space and not time.
Even that picture may help you :-)
 
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