Representing spin operators in alternate basis

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Homework Help Overview

The discussion revolves around finding the matrix representation of the spin operators ##\hat{S}_x, \hat{S}_y, \hat{S}_z##, and ##\hat{S}^2## in the ##S_x## basis. Participants are exploring the implications of changing the basis and the definitions of the operators involved.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the transformation of basis vectors under the action of the operators and question the eigenvectors associated with ##S_x##, ##S_y##, and ##S_z##. There is a consideration of whether to define operators in terms of their action on different basis vectors and the implications of using a similarity transformation versus other methods.

Discussion Status

The discussion is ongoing, with participants raising questions about the definitions and relationships between the operators in different bases. Some express uncertainty about the eigenvectors of ##S_x## and the applicability of the operator equations in a new basis. There is no explicit consensus, but various interpretations and methods are being explored.

Contextual Notes

Participants note the challenge of representing operators in a different basis and the potential confusion regarding the definitions of basis vectors. There is an acknowledgment that the operator forms remain unchanged regardless of the basis, but the representation may differ.

pondzo
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Homework Statement



I want to find the matrix representation of the ##\hat{S}_x,\hat{S}_y,\hat{S}_z## and ##\hat{S}^2## operators in the ##S_x## basis (is it more correct to say the ##x## basis, ##S_x## basis or the ##\hat{S}_x## basis?).

Homework Equations



$$\hat{S}^2|s,m_s\rangle=s(s+1)\hbar^2|s,m_s\rangle$$
$$\hat{S}_z|s,m_s\rangle=m_s\hbar|s,m_s\rangle$$
$$\hat{S}_x|s,m_s\rangle=\frac{1}{2}(\hat{S}_++\hat{S}_-)|s,m_s\rangle$$
$$\hat{S}_y|s,m_s\rangle=\frac{1}{2i}(\hat{S}_+-\hat{S}_-)|s,m_s\rangle$$
$$\hat{S}_{\pm}|s,m_s\rangle=\sqrt{s(s+1)-m_s(m_s \pm 1)}\hbar|s,m_s \pm 1\rangle$$

3. The Attempt at a Solution


Finding these in the ##S_z## basis is simple enough. All I need to do is investigate how the basis vectors ##\{|\frac{1}{2},\frac{1}{2}\rangle \equiv |\alpha\rangle, |\frac{1}{2},\frac{-1}{2}\rangle\equiv |\beta\rangle\}## transform under the action of the operator i wish to represent. Then the columns of the matrix become the image of the basis vectors under the operation. However, I'm not sure what the eigenvectors (basis vectors) of ##S_x## are. On top of that, the actions of the operators i have supplied would no longer apply in a different basis, would they? I would prefer to do it via this method rather than using a similarity transform if possible. Thanks.
 
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Would I do it by defining the operators as follows?

##\hat{S}^2|s,m_s\rangle=s(s+1)\hbar^2|s,m_s\rangle##
##\hat{S}_x|s,m_s\rangle=m_s\hbar|s,m_s\rangle##
##\hat{S}_+=\hat{S}_y+i\hat{S}_z##
##\hat{S}_-=\hat{S}_y-i\hat{S}_z##
Which both imply that:
##\hat{S}_y=\frac{1}{2}(\hat{S}_++\hat{S}_-)##
##\hat{S}_z=\frac{1}{2}(\hat{S}_+-\hat{S}_-)##

And with the basis vectors of ##S_y##, ##|\alpha\rangle## and ##|\beta\rangle## defined as before?
 
pondzo said:
the basis vectors ##\{|\frac{1}{2},\frac{1}{2}\rangle \equiv |\alpha\rangle, |\frac{1}{2},\frac{-1}{2}\rangle\equiv |\beta\rangle\}## t
Which eigenvectors are they, ##S_x##, ##S_y##, or ##S_z##?
pondzo said:
However, I'm not sure what the eigenvectors (basis vectors) of SxSxS_x are.
Find out ##S_x## in matrix form in the basis of the eigenvectors of ##S_z## (this is the most common form found in any literature) then find its eigenvalues as well as its eigenvectors (in the basis of the eigenvectors of ##S_z##).
pondzo said:
On top of that, the actions of the operators i have supplied would no longer apply in a different basis, would they?
The operator equations you wrote above are the action on an eigenvector of ##S_z##. Moreover, the forms of those equation are in the basis-free, operator forms, therefore no matter which basis you chose the form of the above equations will not change. However, if you redefine the notation ##|s,m_s\rangle## to be the eigenvector of ##S_x##, then those equations will indeed look different.
pondzo said:
I would prefer to do it via this method rather than using a similarity transform if possible. Thanks.
It's not clear to me which method you were referring to. To be honest, in matrix form I know no other way to transform a matrix from one basis into another one unless using the usual similarity transformation.
 
Last edited:
This belongs in the advanced physics forum IMO.
 

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