Resistance and ohm's law with light bulb

In summary, the resistance of a tungsten filament in a light bulb is 0.07 ohm and its length is 27 cm. Using the equation R=p(L/A), we can find the area A by rearranging the equation to A=(pL)/R. With the given values of resistivity and length, the area is calculated to be 2.4x10^-9 m^2. Using the formula for the area of a circular cross section, d=2*sqrt(A/pi), we can determine that the diameter of the filament is approximately 1.9 mm.
  • #1
trustabdy
19
0

Homework Statement



the tungsten filament of a light bulb has a resistance of .07 ohm. if the filament is 27 cm long, what is the diameter



Homework Equations



R= p(L/A)

Area of a circular cross section = (PiD^2/4)

The Attempt at a Solution



R= p(L/A) A= (pL)/r

Homework Statement



resistance .07 ohm. lengh= .27m, resistivity= 5.6x10^-8
diameter ?

Homework Equations



A= (pL)/r
 
Physics news on Phys.org
  • #2
can i get some help
 
  • #3
Ok, you have the right equations. From the last equation you wrote and the values you listed, what is the area A?

Once you have that, find the diameter from d=2*sqrt(A/pi).
 

1. What is resistance?

Resistance is the measure of a material's ability to impede the flow of electric current. It is represented by the symbol "R" and is measured in ohms (Ω).

2. What is Ohm's law?

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points. This relationship is represented by the equation I=V/R, where I is the current in amperes, V is the voltage in volts, and R is the resistance in ohms.

3. How does a light bulb demonstrate resistance and Ohm's law?

A light bulb demonstrates resistance by converting electrical energy into light and heat energy. As the current flows through the filament of the light bulb, it encounters resistance and causes the filament to heat up, producing light. The amount of current flowing through the filament is directly proportional to the voltage applied, which follows Ohm's law.

4. How does the resistance of a light bulb affect its brightness?

The resistance of a light bulb directly affects its brightness. As the resistance increases, the amount of current flowing through the filament decreases, resulting in a dimmer light. This is because the filament is not heating up as much and producing less light. Similarly, a decrease in resistance will result in a brighter light.

5. Can resistance and Ohm's law be applied to other electrical components?

Yes, resistance and Ohm's law can be applied to various electrical components, including resistors, capacitors, and conductors. These principles are fundamental in understanding and analyzing the behavior of electric circuits and are widely used in the field of electronics.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
732
  • Introductory Physics Homework Help
Replies
19
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
1K
Replies
6
Views
1K
  • Classical Physics
2
Replies
57
Views
7K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
12
Views
7K
  • Introductory Physics Homework Help
Replies
21
Views
9K
  • Introductory Physics Homework Help
Replies
9
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
1K
Back
Top