Resistance and the length of the wire

AI Thread Summary
Doubling the length of a wire results in a doubling of its resistance, which also leads to a reduction in the electric field and current. This suggests that resistance may not solely be an intrinsic property of the material but rather a combination of factors affecting current flow. The discussion highlights the relationship between electric field, voltage, and current, raising questions about which factor influences the others. Additionally, increasing the cross-sectional area of the wire can double the current by increasing the number of charge carriers, thereby reducing resistance. The conversation ultimately explores the complex interplay between voltage, current, and resistance in electrical circuits.
Ott Rovgeisha
Messages
76
Reaction score
5
Hi!
The question is simple, seemingly...

Doubling the length of a wire, doubles the resistance of the wire...

Why?

There is one interesting point to it:

Doubling the length of the wire also makes the ELECTRIC FIELD weaker TWO times.
That automatically makes the current smaller two times...

We know that making the resistance bigger 2 times, makes the current smaller 2 times.

I see a parallel here! It seems that resistance is NOT necessarily a property of the matter itself, rather it is the combination of factors that make the current smaller than it would be if there were no such factor present (e.g making the wire longer). So it seems to me that the "resistive factor" here is the weakening of the electric field...

Any opinions?

Kind regards!
 
Physics news on Phys.org
Ott Rovgeisha said:
Doubling the length of the wire also makes the ELECTRIC FIELD weaker TWO times.
The electric field is due to the current flowing through the wire, not the resistance of the wire.
 
256bits said:
The electric field is due to the current flowing through the wire, not the resistance of the wire.
I assure you that this is not true!
The electric field in the wire is due to the surface charge gradient ON the conductor. The surface charge gradient is caused by the battery! Electric field CAUSES the current, not vice versa!
 
Ott: what is your logic if instead of doubling the length of the wire, you double the cross sectional area of a cylindrical wire?
 
Ott Rovgeisha said:
I assure you that this is not true!
The electric field in the wire is due to the surface charge gradient ON the conductor. The surface charge gradient is caused by the battery! Electric field CAUSES the current, not vice versa!
You are blinding me by science, as the song goes, but I think I might see what you are saying.
Resistivity is tabulated for materials, but to obtain a value, one has had to previously measure the voltage and current through a section of the material.
Hmm.
Then it is back to a catch-22 situation, or chicken and egg question of which determines which - ie voltage, current, resistance.

What about what qsal has mentioned?
 
gsal said:
Ott: what is your logic if instead of doubling the length of the wire, you double the cross sectional area of a cylindrical wire?

Doubling the cross sectional area doubles the number of charge carriers per area, which in turn directly doubles the current. It is a condition, by which the current is able to be twice as high compering to the situation where the wire is thinner: therefore we can again, say that the resistance to the current is less.
 
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'
So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
Back
Top