Resistance calculation in a cube

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SUMMARY

The discussion focuses on calculating the equivalent resistance across two adjacent vertices of a cube where each edge and body diagonal is represented by a one-ohm resistor. The solution involves recognizing the parallel and series combinations of resistors, specifically identifying groups of resistors labeled as green, blue, and red in the provided figures. The final equivalent resistance can be determined using star and delta transformations, which are essential for simplifying complex resistor networks.

PREREQUISITES
  • Understanding of electrical circuits and Ohm's Law
  • Familiarity with resistor combinations: series and parallel
  • Knowledge of star and delta transformations in circuit analysis
  • Basic skills in analyzing 3D geometric structures in electrical contexts
NEXT STEPS
  • Study the principles of star and delta transformations in more depth
  • Learn how to calculate equivalent resistance in complex resistor networks
  • Explore 3D circuit analysis techniques for better visualization
  • Review examples of equivalent resistance calculations in polyhedral structures
USEFUL FOR

Electrical engineering students, circuit designers, and anyone interested in advanced resistor network analysis will benefit from this discussion.

cooltwins
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Homework Statement



each edge of a cube is built with a one ohm resistor, body diagonals are also built with one ohm resistors each. find out equivalent resistance across any two adjacent vertices.

Homework Equations



i guess it deals with star and delta transformations

The Attempt at a Solution



i'm attempting the question at the present and will post my solution once I'm done with the question.

hoping for a reply from you,

cheers
cooltwins
 
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come on guys,

any help...

i've been trying frantically with no results. i could do with some help
 
hay..

just look at the network. here resistor a,b, and c(color green) are parallel and d,e,f,g,h,i(blue) are in parallel and j,k,l(red) are parallel in figure 1. While all these(green-blue-red) are connected in series. Look figure 2.
 

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thanks for taking the effort mate :) got the solution :D
thanks again
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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