Resonance and Bandwidth Question

AI Thread Summary
Bandwidth is not always centered on the resonance frequency, as demonstrated in some band-pass filter examples. For a 2nd-order biquad band-pass filter, the resonant frequency is positioned at the geometric mean of the two bandedges in a log-frequency scale. This means that if the -3.01 dB points are chosen for the bandedges, the resonant frequency aligns with the arithmetic mean of their logarithmic values. Understanding this relationship is crucial for accurately analyzing filter behavior. The discussion clarifies the nuances of resonance and bandwidth in filter design.
tomizzo
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So, I've been covering these concepts recently in a few of my classes, and I'm wondering if the bandwidth is always centered on the resonance frequency?

I assumed it was. However, in a recent problem given, it is shown that the bandwidth of a band-pass filter was not centered about the resonance frequency. I've been looking this up on the internet but couldn't find any info. Any help?
 
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for a 2nd-order biquad band-pass filter, in the log-frequency scale (not the linear-frequency scale), the resonant frequency is in the middle of pass band. that means if you pick the two bandedges (usually the -3.01 dB points, but it could be any level as long as it's the same for the upper bandedge and lower bandedge), the resonant frequency is at the geometric mean of the two bandedges. that is the same as saying that the log of the resonant frequency is at the arithmetic mean of the logs of the two bandedges.
 
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