Mathematica Resonance and rules for mathematical equations

AI Thread Summary
The discussion revolves around calculating the wavelength of the lowest note that can resonate in a 42 cm air column closed at both ends. The key equation used is l = nλ/2, where l is the length of the air column, n is the harmonic number, and λ is the wavelength. To derive the wavelength, the equation is rearranged to λ = 2l/n. The steps involve multiplying both sides by 2, simplifying, and then isolating λ. Additionally, resources for refreshing algebra skills are shared, including links to online algebra courses and practice sites, aiding those needing further assistance with mathematical concepts.
Spookie71
Messages
16
Reaction score
0

Homework Statement



What is the wavelength of the lowest note that can resonate within an air column 42 cm in length and closed at both ends.

Homework Equations



Given: l = 42 cm
n = 1

Required: \lambda

Analysis: l = \frac{n\lambda}{2}

therefore \lambda = \frac{2l}{n}

I don't know how this came to be, could someone please explain.

I've just gone back to high school after 15 years and would appreciate if you could also forward me on to some good links for rules for mathematical equations such as these.

Thanks
Scott
 
Physics news on Phys.org
The steps to go from:

l = \frac{n\lambda}{2} to \lambda = \frac{2l}{n} ?

start at:

l = \frac{n\lambda}{2}

first multiply both sides by 2.

that gives:

2l = 2\times \frac{n\lambda}{2}

on the right side, the 2 in the numerator cancels with the 2 in the denominator, so

2l = n\lambda

Then divide both sides by n.

\frac{2l}{n} = \frac{n\lambda}{n}

on the right side, the n in the numerator cancels with the n in the denominaotr. so,

\frac{2l}{n} = \lambda

Then just switch sides.

\lambda = \frac{2l}{n}
 
Thanks Learningphysics for helping

Scott
 
Back
Top