Resonance states and complex energies

ismaili
Messages
150
Reaction score
0
I'm reconsidering the problem of resonance states.
We know that the resonances in QM are described as the complex energy poles in the scattering amplitude. In the version of QFT, the resonances are described by the complex mass poles of the scattering matrix.
In QFT, I can understand that the masses of intermediate particles develops imaginary masses from loop corrections.
But in the case of QM, I don't quite understand the situation. I read from a book that because the wavefunction of the unstable state extends to infinity. Hence the boundary condition changes (different from bound state's), that's why the complex energy. (The complex energy is still the eigenvalue of the Hamiltonian.)
But I remember that we can prove that the eigenvalues of a Hermitian operators are always real. Like the following proof in the braket language,
from
A|a'\rangle = a'|a'\rangle and \langle a''|A = a''^*\langle a''|
where A is an Hermitian operator and a',a'' are its eigenvalues.
We times the first equation with \langle a''|, the second equation with |a'\rangle, then substract,
\Rightarrow (a' - a''^*)\langle a''|a'\rangle = 0
now we select a' = a'', then we conclude that a' is real.
So, eigenvalues of a Hermitian operator must be real.

In short, my question is,
(1) is the complex energy of resonance in QM the eigenvalue of Hamiltonian?
(2) If (1) is true, then how to explain the breakdown of the proof I wrote above?

Thanks for any ideas.
Sincerely
 
Physics news on Phys.org
answer

(1): No
 
malawi_glenn said:
answer

(1): No
thanks!
So...the complex energy poles are...? :shy:
 
Have you gone through the derivation of the S-matrix in non relativistic quantum mechanics?
 
malawi_glenn said:
Have you gone through the derivation of the S-matrix in non relativistic quantum mechanics?

Actually I haven't gone though the detailed derivation of the S-matrix in non-relativistic quantum mechanics.
I briefly glanced over the section about resonance in Sakurai's book just now.
Do you mean that the resonance energy is the eigenvalue of the sum of the Hamiltonian and the "centrifugal potential?" So, the resonance energy is not the eigenvalue of the Hamiltonian.
But in this way, the sum of Hamiltonian and the centrifugal potential is a Hermitian operator too. Hence the eigenvalues must be real, isn't it?
Could you hint me the key ideas of how to develop the imaginary part of the resonance complex energy?
Thanks.
 
Sakurais book is not good for theory of resonance scattering, at least if you want to do it with S-matrix etc.

Have I implied all the things you are asking for? The resonance is a peak in the cross section.


The Scattering chapter of Merzbacher is quite good.

Anyway, in sakurai, you'll see that the resonance energy is obtained by doing a local taylor expansion of cot(delta_l). But you have already assumed the existence of a resonance etc, so its not so good for resonance scattering as I mentioned.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
According to recent podcast between Jacob Barandes and Sean Carroll, Barandes claims that putting a sensitive qubit near one of the slits of a double slit interference experiment is sufficient to break the interference pattern. Here are his words from the official transcript: Is that true? Caveats I see: The qubit is a quantum object, so if the particle was in a superposition of up and down, the qubit can be in a superposition too. Measuring the qubit in an orthogonal direction might...
Back
Top