(a) Find the resultant force on a negative charge of -3q, placed at the center of a square of side b, which has charges on the 4 corners, respectively, q, 2q, -4q, 2q in clockwise order. (Magnitude and direction)
F= k*q1*q*(1/ r^2)
Ftotal= F15 + F25 + F35 + F45
The Attempt at a Solution
I drew the figure, and see that r = square root 2 *b* (1/2)
One question is that F25 and F45 are equal and opposite. Do they cancel each other out? If so, I wouldn't have to calculate the forces for those, yes?
I'm just a little confused. Sorry if it's super easy.