Undergrad How to Determine N from Refraction Angles and Constants?

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The discussion focuses on reverse engineering refraction using angles and constants. A user seeks to determine the refractive index (N) based on given angles of incidence (I) and refraction (R), along with a constant (k). Clarifications are made regarding the conventional definitions of angles and the role of the normal vector in Snell's law. The conversation highlights the realization that the cosine of the angle difference can be used to derive the necessary angles for solving the problem. Overall, the participants work towards a clearer understanding of the relationship between angles and refraction.
GabrielCoriiu
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I'm trying to reverse engineer refraction. So given I, R and k in the image, what is N so that sin(θ1)/sin(θ2) = k ?
upload_2019-3-10_16-39-25.png
 

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Hello Gabriel, ##\qquad## :welcome: ##\qquad## !
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GabrielCoriiu said:
reverse engineer refraction
Fine, but it would be more sensible to define ##\theta_1## and ##\theta_2## in the conventional manner. The way it looks now makes ##\theta_2## appear completely random to me ...
 
Hi BvU, thank you for the warm welcome. I've changed the image in the original post, I hope this makes it more clear :)
 
GabrielCoriiu said:
what is N
##\vec N## is the normal vector. It doesn't occur as a vector in Snellius' law.

However, I think I do not understand your question.
 
To rephrase the question, what should the surface orientation be, in order for the refracted ray to focus on a specific point, given the light direction and index of refraction.
 
There is no question of focusing: parallel in is parallel out!
Are you asking about finding a given ##\ \theta_1 - \theta_2 ## ?
 
Hmmm,

I've just realized that cos (θ1 - θ2) is I⋅R, supposedly they are unit vectors. I can now get θ1 and replace it in Snell's law and solve for θ1, which is exactly what I want :biggrin:

Thanks BvU!
 
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