Reverse Product Rule: Understanding its Application in Integration

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SUMMARY

The discussion focuses on the application of the reverse product rule in integration, specifically the formula \(\int uv' = uv - \int vu'\). A participant questions the notation used by their teacher, who designated \(a\) as \(u\) and \(b\) as \(v\) without explicitly stating \(v'\). The correct application of integration by parts requires proper identification of \(u\) and \(dv\), and the participant is advised to include the differential notation in their calculations. The integration of the function \(a*b = \frac{e^{-y}}{y}\) is also mentioned, emphasizing the need for clarity in variable representation.

PREREQUISITES
  • Understanding of integration techniques, specifically integration by parts.
  • Familiarity with the notation of derivatives and differentials.
  • Basic knowledge of functions and their representations in calculus.
  • Ability to manipulate algebraic expressions involving functions.
NEXT STEPS
  • Study the formal definition and application of integration by parts.
  • Practice problems involving the reverse product rule with various functions.
  • Learn how to correctly identify and differentiate between \(u\) and \(dv\) in integration.
  • Explore examples of integrating products of functions, particularly exponential functions.
USEFUL FOR

Students studying calculus, particularly those learning integration techniques, as well as educators looking to clarify the application of the reverse product rule in teaching contexts.

brandy
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Homework Statement


i'm sorry i know I've been bombarding physics forums with questions but i need help :p
using reverse product rule \int uv' = uv - \int vu'
and say i have a*b
i noticed my teaher said that a=u and b=v not v' and he simly made that into a v' by deriving.
is there a point to this if so what is the point and is this something he is likely to have done on purpose or by accident.


Homework Equations


...and yes a*b = e^-y /y

The Attempt at a Solution


i attempted, but failed miserably.
 
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One of the things you are NOT doing that you should is including the "dx" or "dt" or whatever the variable of integration is. The correct statement of "integration by parts", which is, as you say, the "reverse product rule", is \int udv= uv- \int vdu.

Now, I don't know what you mean by "say I have a*b". Do you mean you are trying to integrate \int a(x)b(x)dx? In that case, you could try u= a, dv= bdx, then find du by differentiating and find v by integrating.
 

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