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[sloved]reversing order of integration of double integral qns.
pls refer to attached picture.
intially upper and lower limits are , x^2 < y< x^3 and 1<x<1
sketched y=x^2 and y= x^3. => sqrt(y) =x and cube root (y) = x
divide the area into 3 section.
new limits of dxdy
sqrt(y) <x< cube root (y) with 0<y<1 ,
and 0<x< sqrt(y) with 0<y< 1, ( for ve x and +ve y portion of x^2 graph)
and cube root (y)< x< 0 with 1<y<0 ( for ve x and ve y portion of x^3 graph)
but the answer i have shows a different answer. guess i am wrong, but anyone can tell me which part?
attached is a graph i tried to draw( pardon my IT skills=P)
Homework Statement
pls refer to attached picture.
Homework Equations
The Attempt at a Solution
intially upper and lower limits are , x^2 < y< x^3 and 1<x<1
sketched y=x^2 and y= x^3. => sqrt(y) =x and cube root (y) = x
divide the area into 3 section.
new limits of dxdy
sqrt(y) <x< cube root (y) with 0<y<1 ,
and 0<x< sqrt(y) with 0<y< 1, ( for ve x and +ve y portion of x^2 graph)
and cube root (y)< x< 0 with 1<y<0 ( for ve x and ve y portion of x^3 graph)
but the answer i have shows a different answer. guess i am wrong, but anyone can tell me which part?
attached is a graph i tried to draw( pardon my IT skills=P)
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