Revolution about horizontal and vertical lines

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Homework Help Overview

The problem involves using the shell method to find the volume generated by rotating the area between the curves y = x + 2 and y = x² about the x-axis. Participants are exploring the setup of the integral and the calculations involved.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to set up the integral for the shell method but expresses confusion about the correctness of their approach. They question whether they are missing crucial elements in their setup. Other participants suggest examining the limits of integration and the calculations involved in the antiderivative.

Discussion Status

Participants are actively discussing the setup of the integral and the calculations. Some guidance has been offered regarding the limits of integration and the need to consider the correct orientation of the curves. There is acknowledgment of potential errors in the calculations, but no consensus has been reached on the final approach.

Contextual Notes

There is mention of the requirement to use the shell method and the need to divide the problem into two separate integrals, indicating constraints in the problem-solving process.

cathy
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Homework Statement



Use shell method to find volume.
y=x+2
y=x^2
rotate about the x-axis




2. The attempt at a solution

I cannot seem to solve this. I thought this was the way to solve it, but I don't understand if I am missing something crucial.
This is how I set up the integral.

v=integral from 1 to 4 (2pi* y * (y-2-sqrt(y))
This is not giving me the correct answer. Is this that way to set this up?
I also tried the same integral from 0 to 4, and cannot determine what I am doing wrong.
I would appreciate any help.
 
Last edited:
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hi cathy! welcome to pf! :smile:
cathy said:
Use shell method to find volume.

v=integral from 1 to 4 (2pi* y * (y-2-sqrt(y))
This is not giving me the correct answer. Is this that way to set this up?
I also tried the same integral from 0 to 4, and cannot determine what I am doing wrong.

let's see … you're using cylindrical shells of radius y, thickness dy, and length x2 - x1

and that should be between where they meet, at (0,0) and at (2,4): ie for y between 0 and 4

so you second try should work …

can you show us your calculations?​
 
hello!
well, i tried the second one again, like you said, and here are my calculations:

taking the antideriv of,
y^2-2y-y^3/2
antideriv would be:
1/3y^3 - y^2 - 2/5y^5/2
plugging in 4, I get
64/3 -16 -64/5 = -112/15 *2pi
= -224/15pi
and that is not correct

Did I do something wrong here? Please advise.
 
(just got up :zzz:)

looks ok (apart from everything being minus what it should be, since x2 > x+2) :confused:

have you tried +224/15π ?
 
Ohh. i actually see the problem. since it's required for me to do shells, the problem needed to be divided into two separate integrals.
thank you for your help tiny-tim :)
 

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