Rewriting a symbolic Summation

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SUMMARY

The forum discussion focuses on transforming the summation ∑cos²(πn / 4) from summation form to an algebraic form. Users reference WolframAlpha for assistance, which provides the equivalent summation as ∑(1 + cos(πn / 2)) from -N to N. The standard method for evaluating such summations involves using the formula for the sum of cosines, specifically ∑_{n=a}^{b} cos(nw) = (1/2)∑_{n=a}^{b} (e^{inw} + e^{-inw}), which simplifies the process by leveraging geometric series.

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user3 said:
Consider this Summation: ∑cos^2 (∏*n / 4) limits: -N to N

when I type that on wolframAlpha I get the following:

http://www.wolframalpha.com/input/?i=summation+(1++cos(pi+n+/+2))+from+-N+to+N


I have no Idea how it was performed though.


how Can I transform this from summation form to this other algebraic form?

Pick a value for N, and expand the summation.
Pick a different value for N, and expand the summation.
After you do this a few times, maybe you can discover a pattern.
 
user3 said:
Consider this Summation: ∑cos^2 (∏*n / 4) limits: -N to N

when I type that on wolframAlpha I get the following:

http://www.wolframalpha.com/input/?i=summation+(1++cos(pi+n+/+2))+from+-N+to+N


I have no Idea how it was performed though.


how Can I transform this from summation form to this other algebraic form?

Standard method:
\sum_{n=a}^{b} \cos(nw) = \frac{1}{2}\sum_{n=a}^{b} \left(e^{inw} + e^{-inw} \right)
This is a sum of two geometric series ##\sum r^n## with ##r = e^{iw}## and ##r = e^{-iw}##.
 

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