I Riddle: Where is Epsilon in Bohr Model of Atom?

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AhmedHesham
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Hi curious people
Today i had a lecture about bohr model of the atom .we know that the total energy of electron in orbit is minus e squared divided by 8 pi times epsilon times R of the orbit . this is written in my book and i agree with this .But when the author writes a formula for an emitted photon he writes the difference of the law mentioned above but without epsilon . why ?
Thankes
 
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AhmedHesham said:
this is written in my book

Which book?
 
We are curious, not psychics.
 
PeterDonis said:
Which book?

His book! He just said so! :wink:

OP, we're looking for the book's title, and author, and if you can do a good job, maybe a scan of that page. If not, please write the entire formula.
 
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This is a picture from the book
 

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haushofer said:
We are curious, not psychics.
There is no such thing as psychic.
- Patrick Jane
 
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I have no idea what units the equation you posted is supposed to be in. There's a missing electron mass, for one thing.
 
Vanadium 50 said:
I have no idea what units the equation you posted is supposed to be in. There's a missing electron mass, for one thing.

No, it's not missing. This formula is in terms of the ##n^{th}## Bohr radius ##r_n##, which is given by:

##r_n = \dfrac{n^2 \hbar^2}{Z e^2 m_e}##

(where ##Z## is the number of protons in the nucleus, and ##m_e## is the mass of the electron)

The answer to the original poster's question is that they are using units where ##\epsilon_0 = 1##.
 
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Ah...it's buried in the r's. I see,
 
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stevendaryl said:
he answer to the original poster's question is that they are using units where .

Are you sure? Isn't it buried in the r's as well?
 
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No ...i think it is missing
We always us SI in my institute
 
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