If f,g are Riemann integrable on [a,b], then for c,d real numbers,
(let I denote the integral from a to b)
I (cf + dg) = c I (f) + d I (g)
The Attempt at a Solution
I have the proofs for
c I(f) = I (cf)
I (f+g) = I (f) + I(g)
I'm wondering how would I put them together to prove the statement?
Can I just say that because I know these 2 propositions are true, then any linear combination would also work?