Rigid Rod Motion: Analysis of v, a, and Initial Velocity Cases

  • Thread starter Thread starter zorro
  • Start date Start date
  • Tags Tags
    Motion Rod
AI Thread Summary
The discussion revolves around the motion of a light rigid rod on a smooth horizontal surface, focusing on the initial velocity and acceleration of its ends. It explores various scenarios where one end moves upward with constant velocity while the other end experiences different conditions of initial velocity and acceleration. Key concepts include the center of mass (C.O.M.) and relative velocity in analyzing the rod's motion. Participants are considering how these principles apply to the different cases presented. The analysis aims to clarify the dynamics of the rigid rod under the specified conditions.
zorro
Messages
1,378
Reaction score
0

Homework Statement



A light rigid rod is placed on a smooth horizontal surface. Initially the end A begins to move vertically upward with constant velocity v and centre of the rod upward with a velocity v/2 having downward acceleration a/2. The other end moves downward with

a) 0 initial velocity having zero acceleration
b) 0 initial velocity having a downward acceleration
c) non-zero initial velocity and zero downward acceleration
d) all of the above.

The Attempt at a Solution



Does it involve the concept of C.O.M. or relative velocity?
 
Physics news on Phys.org
Bump!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top