Rocket Car Acceleration: Solving for a0 with Latest Materials and Technology

[ProBasket]

A rocket car is developed to break the land speed record along a salt flat in Utah. However, the safety of the driver must be considered, so the acceleration of the car must not exceed 5g (or five times the acceleration of gravity) during the test. Using the latest materials and technology, the total mass of the car (including the fuel) is 6000 kilograms, and the mass of the fuel is one-third of the total mass of the car (i.e., 2000 killograms). The car is moved to the starting line (and left at rest), at which time the rocket is ignited. The rocket fuel is expelled at a constant speed of 900 meters per second relative to the car, and is burned at a constant rate until used up, which takes only 15 seconds. Ignore all effects of friction in this problem.

Find the acceleration a0 of the car just after the rocket is ignited.

wouldnt i just use this formula: v_f = v_i + v_{ex}*ln(m_i/m_f)
but i don't see how i would find the acceleration if there is no a. unless i solve for V_i, which is ..v_i = v_f - v_{ex}*ln(m_i/m_f) Dm/dt and take the derivative? which should give me the acceleration right? a = -v_{ex}/m right?

 

[thepatientmental]

Yes, you are correct. To find the acceleration a0 of the car, we can use the formula a = -v_{ex}/m, where v_{ex} is the exhaust velocity of the rocket fuel and m is the mass of the car at any given time. However, since the mass of the car is constantly changing as the fuel is being burned, we need to take the derivative of the formula v_i = v_f - v_{ex}*ln(m_i/m_f) Dm/dt with respect to time in order to find the acceleration. This will give us a = -v_{ex}*d(m_i/m_f)/dt.

In this case, the rocket fuel is being burned at a constant rate, so the derivative of the mass with respect to time will just be a constant value. Therefore, we can simplify the formula to a = -v_{ex}/m_f * dm/dt. Since we know the mass of the car at the start (6000 kg) and the mass of the fuel (2000 kg), we can find the value of dm/dt by dividing the mass of the fuel by the time it takes to burn (15 seconds).

So, a0 = -900 m/s / 2000 kg * (2000 kg / 15 s) = -60 m/s^2. This means that the acceleration of the car just after the rocket is ignited is -60 m/s^2 or -6g. This is well below the safety limit of 5g, ensuring the safety of the driver during the test.

In conclusion, by using the latest materials and technology, we were able to calculate the acceleration of the rocket car and ensure the safety of the driver during the record-breaking attempt.