Rocket Exhaust Gases: Initial & After 29s Acceleration

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To determine the initial acceleration of the rocket, the thrust must first be calculated using the formula F_s dt = dm·v_r, where dm is the mass flow rate of the exhaust gases and v_r is their relative velocity. The initial thrust can then be used in the equation F = ma, considering the initial mass of 7.30×10^3 kg and accounting for gravitational force. After 29 seconds, the rocket's mass decreases due to the exhaust gases being expelled at a rate of 6.00×10^1 kg/s, necessitating a recalculation of the acceleration. The total force acting on the rocket includes both the thrust and gravitational force. This analysis leads to the determination of the rocket's changing acceleration over time.
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A rocket with initial mass of 7.30×103 kg is fired in the vertical direction. Its exhaust gases are ejected at the rate of 6.00×101 kg/s with a relative velocity of 2.100×103 m/s. What is the initial acceleration of the rocket? What is the acceleration after 29 s have elapsed?
 
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sloanmp said:
A rocket with initial mass of 7.30×103 kg is fired in the vertical direction. Its exhaust gases are ejected at the rate of 6.00×101 kg/s with a relative velocity of 2.100×103 m/s. What is the initial acceleration of the rocket? What is the acceleration after 29 s have elapsed?

I think you will first need to find such a thing like the Thrust of the rocket, which can be obtained by:

F_s dt = dm\cdot\vector{v}_r

With the thrust, which is clearly a force, you can solve for F =ma, m being the initial one (take into account that your rocket is losing mass as it goes up).
Hint: The total force is the thrust + the gravity!
 
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