A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 58.8 m/s^2. The acceleration period lasts for time 10.0 s until the fuel is exhausted. After that, the rocket is in free fall.(adsbygoogle = window.adsbygoogle || []).push({});

Find the maximum height y_max reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.8 m/s^2.

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The way I tackled this problem was I used the equation:

final position = intial position + vt + 1/2(a)(t^2)

I got an answer of 490m, but that doesn't seem to be correct. I'm not sure if I have to use the acceleration given to me in the equation (58.8m/s^2) or the default acceleration due to gravity = 9.8 m/s^2.

This answer (490 m) shows how far the rocket would fall in time t_1 starting from zero velocity. I'm not sure if there's an intial velocity (the problem doesn't state it), but if there is, I'd probably use vf^2 = vi^2 + 2as.

Please help, I think I'm doing something wrong here, the answer "490 m" doesn't seem correct.

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# Rocket Height problem.

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