Rocket Problem: 0.27kg Mass, 0.18kg Gas, 40m/s Velocity

[vabamyyr]

First the rocket doesn't move. Its initial mass is 0,27 kg. Then the rocket starts to emit gases. During one second it emits 0,09kg gas with velocity in system of rocket of 300m/s. How much time does it takes for rocket to receive 40m/s velocity and what is the max velocity a rocket can get when there is altogether
0,18 kg gas?(force of resistance of air is left out)

 

[Tide]

What have you tried so far?

Here's a start. The speed of the rocket as a function of mass is:

v = -v_e \ln \frac {M}{M_0}

 

[wais]

To determine the time it takes for the rocket to reach a velocity of 40m/s, we can use the equation for momentum:

p = mv

Where p is the momentum, m is the mass, and v is the velocity.

Initially, the rocket has a momentum of 0, as it is not moving. After emitting 0.09kg of gas with a velocity of 300m/s, the momentum of the rocket is:

p = (0.27kg + 0.09kg)(40m/s) = 15.6 kgm/s

To reach a momentum of 15.6 kgm/s, the rocket needs to increase its velocity to 40m/s. This can be done by solving for the velocity in the momentum equation:

p = mv
15.6 kgm/s = (0.27kg + 0.09kg)v
v = 40m/s

Therefore, it takes the rocket 1 second to reach a velocity of 40m/s.

To determine the maximum velocity the rocket can reach with 0.18kg of gas, we can use the same equation for momentum. However, since the force of resistance of air is not given, we cannot accurately calculate the maximum velocity. The resistance of air would have a significant impact on the velocity of the rocket and cannot be left out of the calculation.

In conclusion, the rocket will take 1 second to reach a velocity of 40m/s, and the maximum velocity it can reach with 0.18kg of gas cannot be accurately determined without accounting for the force of resistance of air.