A meter stick is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other end just before it hits the floor, assuming that the end on the floor does not slip. (Hint: Consider the stick to be a thin rod and use the conservation of energy principle) Solution on page 6 # HRW 10.63 http://www.nvcc.edu/home/tstantcheva/231files/hrwch10hw.pdf [Broken] Can someone explain the solution to me please?? I do not understand why PE = 1/2 mgl? where did 1/2 come from? How did the first step become ω^(2) equal 3g/L? does v = ωL? how did ωL = sqrt (3gL)? thanks!!