A uniform thin rod of mass m and length l is standing upright on a table, then given a tiny kick so it tips over. The lower end is fixed. Find angular velocity when it hits the table.
The Attempt at a Solution
So I applied conservation of energy.
where vcm is the linear velocity of the CM and ω is the angular velocity of the rod when it hits the floor. vcm=ωl/2
For a thin rod that rotates about one end
So substituting in equation (1) i get
mgl/2=1/2(ωl/2)2 + 1/6m(lω)2
which leads to
But i 've checked the answer and it turns out is ω2=3g/l
where am i wrong?
thanks in advance for your help