- #1

huskydc

- 78

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with a speed of 2.8 m/s, a tire mass of 10 kg and tire radius of 30 cm

the tire cruises up an embankment at 30° for 1 meter

What is the velocity of the tire at the topof the embankment in m/s?

I tried the following:

energy conservation: and end up with something like this:

Final KE =

[ 1/2*M*V^2 + 1/2*I*(V/R)^2 ] - M*g*h (where h = 1m * sin30° )

and I = .45

but I'm not sure if at Final KE, that if there is still the rotational energy, however, I tried solving for V

with both either KE as just .5 m v^2 and .5mv^2 + .5 I (v/r)^2

neither works...hints?